, Energy of Interaction of Point Charges Coulomb\'s Law yields an expression for

Question

,

Energy of Interaction of Point Charges

Coulomb's Law yields an expression for the energy of interaction for a pair of point charges.

V is the energy (in J) required to bring the two charges from infinite distance separation to distance r (in nm).
Q1 and Q2 are the charges in terms of electrons.
(i.e. the constant in the above expression is 2.31×10-19J nm electrons-2)

For a group of "point" charges (e.g. ions) the total energy of interaction is the sum of the interaction energies for the individual pairs.
Calculate the energy of interaction for the arrangement of ions shown in the diagram below.

d = 0.840 nm.

Explanation / Answer

V = 2.31 * 10^(-19) Q1Q2/r

Energy of the arrangement of ions = 2.31 * 10^(-19)/0.840 - 2.31 * 10^(-19)/infinity

=> 2.75 * 10^(-19) J

Hence the energy of the interaction of the arrangement of ions is equal to 2.75 * 10^(-19) J

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