Splitting of a signal in a proton NMR spectrum tells us the hydrogens in the imm

Question

Splitting of a signal in a proton NMR spectrum tells us the hydrogens in the immediate vicinity of the hydrogen giving exhibited by hydrogens at the labeled positions in a first approximation that all coupling constants are equal.) The number of lines exhibited by hydrogen(s) a is. The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is

Explanation / Answer

1) In 1H-NMR number of siglals for a perticular hydogen (or a set of magnetically euivalent protons) depends upon quantity of its neighbouring hydrogens and it is governed by (n +1) rule

where n = number of magnetically euivalent protons

So,

1)

Number of line exibited by Hydrogen a = triplet (total three lines)

Number of line exibited by Hydrogen b = doublets of triplet (total 6 lines)

Number of line exibited by Hydrogen c = triplet (total three lines)

2)

Number of line exibited by Hydrogen a = triplet (total three lines)

Number of line exibited by Hydrogen b = triplrts of triplet (total 9 lines)

Number of line exibited by Hydrogen c = triplet (total three lines)

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