At the very bottom, how do you determine that the water is 0.4 mole? I think i g

Question

At the very bottom, how do you determine that the water is 0.4 mole? I think i get the 2(0.0275) because we need 2 mole of CO2 for the 2H2O. But I don't understand why they added 0.1725 twice first.
Also, since the mole of product gas shown looks confusing, here you go: CO & H2O: 0.1725 mole CO2: 0.0275 mole H2: 0.6275 mole
Lastly, could you please give me some tips on balancing like this one, where you determine mole of reactant gases from the given mole of product gases? Ive always had trouble with this even though it should be really simple.
Thanks. Step 1 One way to proceed is as in Example 4.8 with the alternative pair of reactions: CH4H20- CO3H2 AH298a205813 167 CH4 + 2H2O = CO2 + 4H2 AH298»-164647 BASIS:1mole of product gases containing 0.0275 mol CO2; 0.1725 mol CO:&H20; 0.6275 mol H2 Entering gas, by carbon&oxygen; balances: 0.0275+0.1725- 0.2000 mol CH4 0.1725 + 0.1725 + 2(0.0275) = 0.4000 mol H2O

Explanation / Answer

from the reaction CH4+ H2O---->CO+ 3H2

0.1725 moles of CO requires 0.1725 molesof H2O

for CO2 2*0.0275 moles of H2O

so total water = water used from CO+ water used from CO2 + H2O in the product= 0.1725+2*0.0275+0.1725= 0.4 mole

b) When the product composition is given first identiyfy tie substance. Tie substance does not undergo any change in the process. This makes calculations much simpler even though it is missing in the present problem. Nitrogen from air is inert and it comes from air. It makes Calculations of oxygen easier and rest of the reactants.

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