introduction to genetic analysis If ninety plants from the segregating progeny d
ID: 94630 • Letter: I
Question
introduction to genetic analysis If ninety plants from the segregating progeny derived from a self cross of a heterozygous plant exhibit a dominant phenotype, in theory, how many in the progeny will show the recessive phenotype if the phenotype is controlled by 2 redundant genes? introduction to genetic analysis If ninety plants from the segregating progeny derived from a self cross of a heterozygous plant exhibit a dominant phenotype, in theory, how many in the progeny will show the recessive phenotype if the phenotype is controlled by 2 redundant genes? introduction to genetic analysis If ninety plants from the segregating progeny derived from a self cross of a heterozygous plant exhibit a dominant phenotype, in theory, how many in the progeny will show the recessive phenotype if the phenotype is controlled by 2 redundant genes?Explanation / Answer
Heterozygous plant self crossed.
G1 shows 90 plants dominant phenotype(This number will have both homozygous and heterozygous gentypes)
Punnett square for a self crossed heterozygous plant will show the ratio of dominant phenotype:recessive phenotype as 3:1
Since the recessive phenotype is said to be controlled by 2 redundant genes, the actual ratio as stated above will not change.
The dominant phenotype plants are 90 in number and so the recessive phenotype exhibiting plants will be 30 plants(3:1)
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