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t Visited Getting Started Egg Osmosis (Hyperto...TripAdvisor -New Message Econnect CHEMISTRY M 121 HWSB Question 7 (of 15) neit question 1.00 points 3 out of 5 attenpts Be sure to answer all parts. Assistance Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide: N m glucose ethanol Starting with 480.4 g of glucose, what is the masimum amount of ethanol in grams and in liters that can be obsained by this process (density of ethanol-0.789 g'mL)?Explanation / Answer
Answer – We are given, reaction –
C6H12O6 -----> 2C2H5OH + 2CO2
Mass of glucose = 480.4 g , density of ethanol = 0.789 g/mL
First we need to calculate the moles of glucose
Moles of glucose = 480.4 g /180.15 g.mol-1
= 2.67 moles
From the balanced equation
1 moles of C6H12O6 = 2 moles of C2H5OH
So, 2.67 moles of C6H12O6 = ?
= 5.33 moles of C2H5OH
Mass of C2H5OH = 5.33 moles * 46.07 g/mol
= 245.7 g
Volume of ethanol = mass of ethanol / density of ethanol
= 245.7 g / 0.789 g.mL-1
= 311.4 mL
= 0.311 L
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