Use the information in the table below to determine DG o for the reaction 2NH 3

Question

Use the information in the table below to determine DGofor the reaction

2NH3(g) + 2O2(g) --> N2O(g) + 3H2O(l)

DGo (kJ)

N2(g) + 3H2(g) --> 2NH3(g)

-33.0

4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(l)

-1010.0

N2(g) + O2(g) --> 2NO(g)

174.9

N2(g) + 2O2(g) --> 2NO2(g)

102.6

2N2(g) + O2(g) --> 2N2O(g)

204.2

DGo (kJ)

N2(g) + 3H2(g) --> 2NH3(g)

-33.0

4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(l)

-1010.0

N2(g) + O2(g) --> 2NO(g)

174.9

N2(g) + 2O2(g) --> 2NO2(g)

102.6

2N2(g) + O2(g) --> 2N2O(g)

204.2

Explanation / Answer

(4NH3(g) + 5O2(g)   -->   4NO(g) + 6H2O(l))*1/2   DG1 = -1010/2 =

(2N2(g) + O2(g)   -->    2N2O(g) )*1/2           DG2 = 204.2/2

2NO(g)    ---->     N2(g) + O2(g)                dg3 = -174.9
    

--------------------------------------------

2NH3(g) + 2O2(g) --> N2O(g) + 3H2O(l) DG0 = (-1010/2)+(204.2/2)+(-174.9) = -577.8 Kj

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