(NH4)2CO3(aq) + 2CuF(aq) Cu2CO3(s) + 2NH4F(aq) The molecular equation you determ

Question

(NH4)2CO3(aq) + 2CuF(aq) Cu2CO3(s) + 2NH4F(aq)

The molecular equation you determined in Part B is shown above for your convenience. Examine each of the chemical species involved to determine the ions that would be present in solution. Be sure to consider both the coefficients and subscripts of the molecular equation, and then write this precipitation reaction in the form of a balanced complete ionic equation. Express your answer as a chemical equation including phases. Type an underscore (_) or a carat (^) to add subscripts and superscripts more quickly

Explanation / Answer

the balanced reaction is

(NH4)2C03 + 2 CuF (aq) ---> Cu2C03 (s) + 2 NH4F

now

write the ionic equation

it is

2NH4+ + C032- + 2 Cu+ + 2F- --> Cu2C03 (s) + 2 NH4+ + 2 F-

cancel out the common ions

we get

2Cu+ (aq) + C032- (aq) ----> Cu2C03 (s)

so

the net ionic equation is

2Cu+ (aq) + C032- (aq) ----> Cu2C03 (s)

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