What are the equilibrium partial pressures of CO and CO2 if CO is the only gas p

Question

What are the equilibrium partial pressures of CO and CO2 if CO is the only gas present initially, at a partial pressure of 0.966 atm ?

At 1000 K, Kp = 19.9 for the reaction Fe2O3(s)+3CO(g)?2Fe(s)+3CO2(g).

Part A What are the equilibrium partial pressures of CO and CO2 if CO is the only gas present initially, at a partial pressure of 0.966 atm? Enter your answers numerically separated by a comma. Poco , Pco2 = 10.257, atm Submit My Answers Give Up Give Up Incorrect; Try Again; 5 attempts remaining; no points deducted Your answer does not have the correct number of comma-separated terms. Provide Feedback Continue

Explanation / Answer

given reaction is

Fe203 (s) + 3 CO --> 2Fe (s) + 3 C02

solids are not considered

so

Kp = (pC02)^3 / (pCO)^3

so

Kp = ( pCO2 / pCO)^3

now

consider the given reaction

Fe203 (s) + 3 CO --> 2Fe (s) + 3 C02

using ICE table

at equilibrium

pC0 = 0.966 - 3x

pC02 = 3x

so

Kp = ( pCO2 / pCO)^3

19.9 = ( 3x / 0..966-3x)^3

3x / 0.966 - 3x = 2.71

3x = 2.71 (0.966-3x)

x = 0.2352

so

pC0 = 0.966 - 3x = 0.966 - ( 3* 0.2352) = 0.2604 atm

pC02 = 3x = 3 * 0.2352 =0.7056 atm

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