Wilma determined that the reaction CO (g)+ Cl2 (g) COCL(g) + CI (g) occurred in

Question

Wilma determined that the reaction CO (g)+ Cl2 (g) COCL(g) + CI (g) occurred in a single reversible step. From her experimental collected data she also was determined that the rate constant for the forward reaction (kf) had a value of 1.38 x 10^-28M/sec and the rate constant for the reverse reaction (kr) had a value of 9.3 x 10^10 m/sec when the reaction was run at25.0 degreeC. Given this information: Calculate the equilibrium constant's value (Kc). What would be the Kc value for 2CI (g) + 2 COCI (g) 2 Clz (g) + 2CO (g). In which direction is this reaction is favored? Multiple choice question. If the pressure in the reaction vessel was increased, determine the direction would the reaction would shift to reestablish a new equilibrium position? To the product side To the reactant side No change in direction.

Explanation / Answer

1.

CO(g) +Cl2(g) <==> COCl(g) + Cl(g)

Kc = Kf/kr = (1.38*10^(-28))/(9.3*10^10)

   = 1.5*10^-39

2.

Kc2 = 1/(1.5*10^-39)^2 = 4.4*10^77

3. forwarddirection.

4. no change in direction

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