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PLEASE HELP TO BEST OF ABILITIES WHATEVER YOU CANT ANSEWR IS OK Dilution Set Pre

ID: 942561 • Letter: P

Question

PLEASE HELP TO BEST OF ABILITIES WHATEVER YOU CANT ANSEWR IS OK

Dilution Set Preparation (5 p)   Build a table that clearly indicates how you performed the stock dye dilutions for the calibration curve (Beer’ Law plot). Note, this must be the dilution set you prepared (NOT your partner’s efforts). If you personally worked with more than one dye, and thus prepared more than one dilution set, then include the additional information either in separate tables, or in a well-organized master table.

Dilution set

Molarity of Stock Solution

Volume of stock solution (mL)

Volume of Diluent (mL)

Molarity of mixture

Blue 1

6.96 x 10^-6

9 ml

0 ml

Blue 2

6.96 x 10^-6

7.77 ml

2.23 ml

Blue 3

6.96 x 10^-6

5.57 ml

4.43 ml

Blue 4

6.96 x 10^-6

3.33 ml

6.67 ml

Blue 5

6.96 x 10^-6

1.1 ml

8.9 ml

Dye to diluent ratio (mL)

max

Absorbance (nm)(Y)

Concertation (X)/ Molarity(M)

9:0

.878

628

6.96 x 10^-6

7.77:2.23

.702

628

6.00 x 10^-6

5.57:4.43

.511

628

4.3 x 10^-6

3.33:6.67

.306

628

2.57 x 10^-6

1.1:8.9

.110

626

8.5 x 10^-7

Calibration Plot Results (4 p)   From the absorbance versus concentration (calibration, Beer’s Law) plot(s) of the FD&C dye(s) you worked with (NOT your partner’s efforts), state the R2 value and the equation of the line. Clearly state the max for the work and the inferred molar absorptivity .

Calculations (9 p)   Symbolically state the equations that permitted determining the grams of FD&C food dye per gram of gumball. Define all variables and constants. Next, give one example calculation.

Results Table (6 p)   For the gumballs you and your lab partner analyzed, construct a table for the FD&C dyes your group identified. Include the observed max, the determined molar absorptivity , and the grams of dye per gram of gumball. The reported max, and values should be only those you and your partner generated – any values obtained from other student groups must be noted as such with the appropriate citation/attribution.

Errors Analysis (6 p)   Other than human error, calculation mistakes, accidents and the like, discuss two major sources of error that are inherent to the instrumentation, procedure or experimental design of Project 2 Session 3 Task 3 that will cause the grams of dye per gram of gumball value to be too high. That is, state two major procedural, design or instrumental issues that will result in elevated mass of dye per mass of gumball values no matter how many times the experiment is repeated assuming with each repetition the exact same steps are followed. Trivial sources of error, such as dirty cuvettes will not receive credit.

Dilution set

Molarity of Stock Solution

Volume of stock solution (mL)

Volume of Diluent (mL)

Molarity of mixture

Blue 1

6.96 x 10^-6

9 ml

0 ml

Blue 2

6.96 x 10^-6

7.77 ml

2.23 ml

Blue 3

6.96 x 10^-6

5.57 ml

4.43 ml

Blue 4

6.96 x 10^-6

3.33 ml

6.67 ml

Blue 5

6.96 x 10^-6

1.1 ml

8.9 ml

Explanation / Answer

I am solving the dilution set table, please split the problem into multiple steps, the first part contains 5 sub-parts

Dilution set

Molarity of Stock Solution

Volume of stock solution (mL)

Volume of Diluent (mL)

Molarity of mixture

Blue 1

6.96 x 10^-6

9 ml

0 ml

6.96 x 10^-6

Blue 2

6.96 x 10^-6

7.77 ml

2.23 ml

5.407 x 10^-6

Blue 3

6.96 x 10^-6

5.57 ml

4.43 ml

3.876 x 10^-6

Blue 4

6.96 x 10^-6

3.33 ml

6.67 ml

2.317 x 10^-6

Blue 5

6.96 x 10^-6

1.1 ml

8.9 ml

7.656 x 10^-7

For Blue 1

M1V1 = M2V2

(6.96*10^(-6))(9) = M2(9+0)

M2 = 6.96* 10^(-6) M

For Blue 2

M1V1 = M2V2

(6.96*10^(-6))(7.77) = M2(7.77+2.33)

M2 = 5.407 * 10^(-6) M

For Blue 3

M1V1 = M2V2

(6.96*10^(-6))(5.57) = M2(5.57+4.433)

M2 =3.87 * 10^(-6) M

For Blue 4

M1V1 = M2V2

(6.96*10^(-6))(3.33) = M2(3.33+6.67)

M2 = 2.317 * 10^(-6) M

For Blue 5

M1V1 = M2V2

(6.96*10^(-6))(1.1+8.9) = M2(1.1+8.9)

M2 = 7.656 * 10^(-7) M

Dilution set

Molarity of Stock Solution

Volume of stock solution (mL)

Volume of Diluent (mL)

Molarity of mixture

Blue 1

6.96 x 10^-6

9 ml

0 ml

6.96 x 10^-6

Blue 2

6.96 x 10^-6

7.77 ml

2.23 ml

5.407 x 10^-6

Blue 3

6.96 x 10^-6

5.57 ml

4.43 ml

3.876 x 10^-6

Blue 4

6.96 x 10^-6

3.33 ml

6.67 ml

2.317 x 10^-6

Blue 5

6.96 x 10^-6

1.1 ml

8.9 ml

7.656 x 10^-7

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