need help with these 2 questions. please show the steps you took. 12. Mg (s) + 2
ID: 941186 • Letter: N
Question
need help with these 2 questions. please show the steps you took.
Explanation / Answer
12.
DH = DE+PDV
No of mol of Mg = 2.5/24 = 0.104 mol
PDV = DnRT = (0.104-0)*8.314*298 = 257.7 joule = 0.257 kj
workdone = 0.257 kj
DH0 = -350*0.104 = -36.4 kj
-36.4 = x+0.257
x = -36.657 kj = DE
13.
DHrxn = DHfco2 + 2*DHFso2 - DHfCS2 + 3*dhFo2
-1073.6 = (-393.5-2*296.4) - (x + 3*0)
x = DHfCS2 = 87.3 Kj/mol
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.