2AgNO3 + NaNO3 = Ag2CO3 + 2NANO3 Part A. The coefficients for the correctly bala

Question

2AgNO3 + NaNO3 = Ag2CO3 + 2NANO3

Part A. The coefficients for the correctly balanced equation you see nearby are:

A.      2, 1, 1, 2

B.      1, 1, 1, 1

C.       1, 2, 1, 2

D.      2, 2, 1, 2

Part B. After creating two dimensional analysis-based scenarios to decide, the limiting reagent in this problem given 10.00 g of each reactant is what?

A.      silver nitrate

B.      sodium carbonate

C.       silver carbonate

D.      sodium nitrate

Part C. The mass of sodium nitrate produced in this reaction is solely based upon the limiting reagent and the most sodium nitrate that you can make is:

A. 3.120 g

B. 10.008 g

C. 5.004 g

D. 8.116 g

Part D. The mass of silver carbonate produced is:

A.      3.120 g

B.      10.008 g

C.       8.116 g

D.      5.004 g

Part E. The mass of excess reagent left over is:

A.      3.120 g

B.      6.880 g

C.       5.004 g

D.      8.116 g

Explanation / Answer

The balanced reaction is

a. 2AgNO3 + Na2CO3 = Ag2CO3 + 2NaNO3

ans is 2,1,1,2

b. moles of Na2CO3 = 10g / 105.9888 g/mol = 0.094

moles of AgNO3 = 10g / 169.87 g/mol = 0.058

hence, silver nitrate is limiting reagent.

c. two moles of silver nitrate produce 2 moles of sodium nitrate.

hence moles of sodium nitrate formed = 0.058

mass of sodium nitrate formed = 0.058 moles *84.9947 g/mol = 5.004 g

d. two moles of silver nitrate gives 1 mole of silver carbonate

hence moles of sodium carbonate formed = 0.058

mass of sodium carbonate formed = 0.058 moles *167.8771 g/mol = 10.008g

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