What is the theoretical yield for [MnIII(salpn)(H2O)2](CF3SO3)? Experiment Guide

Question

What is the theoretical yield for [MnIII(salpn)(H2O)2](CF3SO3)?

Experiment Guide:

[MnIII(salpn)(H2O)2](CF3SO3) In a round bottom flask, to a slurry of 1.5 mmoles MnIII(salpn)(AcAc) (0.65 g) in 15 mL of acetonitrile, add 1.5 mmol of trifluoromethanesulfonic acid (triflic acid, 1.5 ml of a 1.0 M solution in acetonitrile) dropwise.

• Stir 15 minutes, filter if some solid remains, then reduce solvent to about 5 ml by rotary evaporation (do not reduce the solvent too much).

• Transfer concentrated solution/slurry to a 100-250 mL beaker. • Add about 25 ml ether to the solution and collect the solid by vacuum filtration.

• When it is dry, determine the yield.

Explanation / Answer

1 mole of product is formed from 1 mole of Mn(III) salt.

Theoretical yield of product formed = 1.5 mmol x 620.751 g/mol = 0.931 g

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