Explain why the conductivity of 0.198 M KBr(aq) is about twice that of 0.099 M K

Question

Explain why the conductivity of 0.198 M KBr(aq) is about twice that of 0.099 M KBr(aq). The 0.198 M KBr consists of K_2^2+ and Br_2^2- ions in solution whereas the 0.099 M KBr only has K+ and Br^- ions in solution. Since the 0.198 M KBr is twice as concentrated as 0.099 M KBr. each ion is allowed to carry twice as much electrical charge in solution. KBr is a weak electrolyte and ionizes twice as much in the 0.198 M KBr as it does in the 0.099 M KBr. There are twice as many ions in solution in 0.198 M KBr than there are in 0.099 M KBr. The nature of the ions in solution for 0.198 M KBr are different than those in the 0.099 M KBr and the ions in the 0.198 M KBr carry the charge better.

Explanation / Answer

The conductivity of 0.198 M KBr is about twice that of 0.998 because there are twice as many ions in solution in 0.198 M KBr than there are in 0.099 M KBr.

KBr < = > K+    + Br-

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.