Based on the data summarized below, answer the following questions: a) Calculate
ID: 938352 • Letter: B
Question
Based on the data summarized below, answer the following questions:
a) Calculate the number of moles of BaSO4 that were collected.
b) Caclulate the number of moles of SO4^2- ion that were in the sample that was taken of the unknown.
c) Calculate the mass of the sulfate in the sample that was taken of the unknown.
d) Calculate the mass percentage of sulfate ion in the sample of the unknown sample.
The data summarized below were collected following the procedures outline for this experiment. (You may refer to page 21 for guidance with these calculations.) Mass of empty beaker 132.862 g Mass of beaker with unknown sample 133.343 g Mass of crucible 41.962 g Mass of crucible with BaSO_4 42.631 g Calculate the number of moles of BaSO_4 that were collected. Calculate the number of moles of SO_4^2- ion that were m the sample that was taken of the unknown. Calculate the mass of the sulfate in the sample that was taken of the unknown. Calculate the mass percentage of sulfate ion in the sample of the unknown sample Calculate the percentage of sulfate ion in potassium sulfate, K_2SO_4. ammonium sulfate, (NH_4)SO_4, and aluminum sulfate hexahydrate, A1_2(SO_4)_3 6H_20. Please show your work below. You may continue on the back of this page if necessary.Explanation / Answer
a. mass of BaSO4 taken = (mass of crucible + unknown sample) - (mass of crucible)
= 42.631 - 41.962 g
= 0.669 g
moles of BaSO4 = mass of BaSO4 / Molar mass of BaSO4
= 0.669 / 233.43g/mol = 2.86 X 10^(-3) moles
b. the no. of moles of sulfate ions = 2.86 X 10^(-3) moles
c.
mass of sulfate in the unknown = 2.86 X 10^(-3) moles * 96.06g/mol = 0.2747 g
d.
mass of unknown taken = (mass of crucible + unknown sample) - (mass of crucible)
= 133.343 - 132.862 g
= 0.481 g
mass % = 0.2747 g / 0.481 g = 47.2 %
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