We are all familiar with the general principles of operation of an internal comb

Q: We are all familiar with the general principles of operation of an internal comb

W = F*d W = F*d since P = F/A thenM; F= P*A W = P*A*d A*d = V then W = P*V P = 100 kPa = 100*10^3 Pa A = 100 cm^2 = 0.01 m2 d = 10 cm = 0.1 m W = (100*10^3)(0.01)(0.1) = 100 J W = 100 J done into the system (since it is being pressurized)

ID: 938159 • Letter: W

Question

We are all familiar with the general principles of operation of an internal combustion engine: the combustion of fuel drives out the piston. It is possible to imagine engines that use reactions other than combustions, and we need to assess the work they can do. A chemical reaction takes place in a container of cross-sectional area 100.0 cm^2; the container has a piston at one end. As a result of the reaction, the piston is pushed out through 10 cm against a constant external pressure of 100 kPa. Calculate the work done by the system in Joules.

Explanation / Answer

W = F*d

since P = F/A

thenM; F= P*A

W = P*A*d

A*d = V

then

W = P*V

P = 100 kPa = 100*10^3 Pa

A = 100 cm^2 = 0.01 m2

d = 10 cm = 0.1 m

W = (100*10^3)(0.01)(0.1) = 100 J

W = 100 J done into the system (since it is being pressurized)

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We are all familiar with the general principles of operation of an internal comb

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