The solubility product constant, A^p, for nickel (II) carbonate is 1.3 x I0^-7 a

Question

The solubility product constant, A^p, for nickel (II) carbonate is 1.3 x I0^-7 at 25DegreeC. a. Write the balancc chemical equation for this dissolving process. b. Write the equilibrium expression. c. Find the maximum molar concentration of all ions in solution and the molar solubility of the solution. 3) The solubility product constant, K^, for calcium hydroxide is 6.5 x 10^-6 at 25DegreeC. a. Write the balance chemical equation for this dissociation in water. b. Write the equilibrium expression. c. Find the molar concentration of all ions in this solution and the molar solubility of the solution. d. Calculate the maximum mass of calcium hydroxide that will dissolve in 100 mL of distilled water at 25DegreeC. 4) A 250 ml. saturated solution of silver chloride is prenared at 25DegreeC. The solubility product constant, K%p, for silver chloride is 1.8 x 10 1 at 25DegreeC. a. Write the balance chemical equation for this dissolving process. b. Write the equilibrium expression. c. Find the molar concentrations of all ions in this solution and the molar solubility of the solution. d. What arc the molar concentrations of all ions in a 500 mL saturated solution of silver chloride at 25DegreeC?

Explanation / Answer

Question 2.

a) Overall reaction: NiCO3(s) <--------> Ni2+(aq) + CO32-(aq)

b) Ksp = [Ni2+] [CO32-]

c) NiCO3(s) <--------> Ni2+(aq) + CO32-(aq)

i. s 0 0

e. 0 s s

1.3x10-7 = s2

s = (1.3x10-7)1/2 = 3.61x10-4 M

[Ni2+] = [CO32-] = s = 3.61x10-4 M

Question 3.

a) Ca(OH)2(s) <--------> Ca2+ + 2OH-

Ksp = [Ca2+] [OH-]2

Ca(OH)2(s) <--------> Ca2+ + 2OH-

i. s 0 0

e. 0 s 2s

6.5x10-6 = s * (2s)2

6.5x10-6 = 4s3

s = (6.5x10-6/4)1/3

s = 0.0118 M

[Ca2+] = s = 0.0118 M

[OH-] = 2s = 2*0.0118 = 0.0236 M

m Ca(OH)2 = M*V * MM

MM = 40 + 16*2 + 2*1 = 74 g/mol

m Ca(OH)2 = 0.0118 mol/L * 0.100 L * 74 g/mol

m Ca(OH)2 = 0.08732 g

Try to solve question 4 by yourself following the same procedure as question 2 and 3, you just have to replace the values. The overall reaction for this question is AgCl(s) ------> Ag+(aq) + Cl-(aq)

Hope this helps

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