UT Tyler CHEM 1312 Sp x How To Take a Screenshot o x c Chegg C biscms/mod/ibis/v

Question

UT Tyler CHEM 1312 Sp x How To Take a Screenshot o x c Chegg C biscms/mod/ibis/view.php 1481432 O 4/16/2015 10:00 PM A 692/100 O4f 02:17 PM 4/14/2015 Gradebook score Attempts Print Calculator Periodic Table Questi 2 of 18 Map 93 95 Given the following information 95 AH 686.8 kJ AS" 352.0 J/K 2D 00 AH 553.0 kJ AS 217.0 J K 98 calculate AG for the following reaction at 298 K 00 A B C 98 12 k J AG 13 00 67 Next Give Up & Vi Ch US 00 ght 20 2015 about us careers partners privacy policy terms of use contact us help O Assignment Informatlon Available From: 4/1/2015 09:00 AM 4/16/2015 10:00 PM Due Date: Polnts Posslble: 00 Grade Category: Graded Descriptlon Poll cles: You can check your answers. You can view solutions when you complete or give LIP on any question. You can keep trying to answer each question until you get it right or give up 5% in your question for each incorrect attempt at that O Help Wlth Thls Toplc C Web Help & VIdeos OTechnlcal Support and Bug Reports 9:09 AM 15/2015

Explanation / Answer

We will need to use hess laws... arrange equations to get our values

for (1)

A+B --> 2D

for (2), we need to inverse and multiply by two. Inversing means changing signs and multiplying means, well... of course multiplying

C --> D

D ---> C (change sign) H = -553 S = +217

2D ---> 2C (multiply by 2) H = -1106 S = +434

As you can see.. if we add

A+B --> 2D

2D ---> 2C

We get

A+B --> 2C which is what we want!

Let us add H and S

H = -686.8 + (-1106 ) = -1792.8 kJ

S = 352  +434 = 786 J/K

For G at 298K

G = H-TS

G = -1792.8 kJ - (298K)(786 J/K)(1kJ/1000J) = -1792.8 kJ-234.23 kJ = -2027.03 kJ

G = -2027.03 kJ

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