Some graph can be used more than once). Please answer Question #14-20 The diseas
ID: 93583 • Letter: S
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Some graph can be used more than once). Please answer Question #14-20 The disease identified in the following pedigree is caused by an autosomal gene. Please answer Question #21-27 The graph represent the mother cell at the G_1 phase of cell cycle a. A b. B c. C d. D e. E The daughter cells after mitosis a. A b. B c. C d. D e. E The daughter cells after mitosis I a. A b. B c. C d. D e. E The daughter cells after mitosis II a. A b. B c. C d. D e. E The cells at the prephase of mitosis a. A b. B c. C d. D e. E The cells at the prephase I of meiosis a. A b. B c. C d. D e. E The cells at the prephase II of meiosis a. A b. B c. C d. D e. E The disease is caused by an autosomal ____ allele (s) a. Dominant b. Recessive c. Either dominant or recessive d. Can not be determined The genotype of I-1 is a. AA b. Aa c. aa d. A? e. a? The genotype of I-2 is a. AA b. Aa c. aa d. A? e. a? The genotype of II-1 is a. AA b. Aa c. aa d. A? e. a? The genotype of II-4 is a. AA b. Aa c. aa d. A? e. a? The genotype of III-1 is a. AA b. Aa c. aa d. A? e. a? For a boy born into the third generation (III), what is chance to have the disease? a. 0% b. 25% c. 50% d. 75% e. 100%Explanation / Answer
14)a
15)b
16)c
17)d
18)e
19)d
20)d
21)b
22)c
23)b
24)b
25)b
26)b
27)b
The given pedigree chart represents autosomal recessive disorder.The male is recessive and infected with the disease where as the female is a carrier of the trait.The offsprings all are carriers for the disease.The chances of an off spring to get the disease is 25% because infected person genotype must be "aa" .Offsprings of the cross Aa x Aa results in 1:2:1 genotype ratio which are AA ,Aa and aa respectively .Therefore the probability of getting the disease in either males or females is 25%.
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