Enter your answer in the provided box in scientific notation. A hydrogen-like io

Question

Enter your answer in the provided box in scientific notation. A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by E =-(2.18 x10^-18 J)Z^2(1/n^2) where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg^80+. Use the equation above to calculate the energy required for the last ionization step: x 10 kJ/mol

Explanation / Answer

Quantum configuration:

Hg: [Xe] 4f14 5d10 6s2

Z = 80; n=6

En = -(2.18 *10-18 J) * 802 * (1/62) = -3.88 *10-16 J

En = (-3.88 *10-16 J * 1 kJ/ 1000 J) / 1 mol = -3.88 *10-19 kJ/mol

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