It was important that the flask be completely dry before the unknown liquid was

Question

It was important that the flask be completely dry before the unknown liquid was added so that water present would not vaporize when the flask was heated. A typical single drop of liquid water has a volume of approximately 0.05mL.

Assuming the density of water is 1.0g/mL, if 6 drops of water were left in the flask how many moles of water would this be?

** Write answer in decimal form to four decimal places.**

Using your answer for question 4, what volume(in mL) would this amount of water occupy when vaporized at 100oC and 1atm?

** Write answer in decimal fom to one decimal place. No units in answer.**

Explanation / Answer

A typical single drop of liquid water has a volume of approximately 0.05mL

It is gien that the number of drops in the flask = 6

Volume of water in flask = number of drops X volume of drop = 6 X 0.05 = 0.3 mL

Density of water = 1g/mL

Mass of 0.3mL = Density X volume = 0.3 grams

Moles of water = Mass of water / molecular weight = 0.3 / 18 = 0.0167 moles

5) Using your answer for question 4, what volume(in mL) would this amount of water occupy when vaporized at 100oC and 1atm

The ideal gas law is

PV = nRT

Where

P = pressure = 1atm

V = volume = ?

n = moels = 0.0167

R = gas constant = 0.0821 L atm / mol K

T = temperature = 100 0C = 273.15 + 100 = 373.15 K

Volume = moles X R X T / P = 0.0167 X 0.0821 X 373.15 / 1 = 0.5116 L = 511.6 mL

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