Having some trouble doing this homework. if someone can please help me out it wo

Question

Having some trouble doing this homework. if someone can please help me out it would be greatly appreciated:)

Reaction:

CaCl2*2H2O(aq) + K2C2O4*H2O(aq) >> CaC2O4*H2O(s) + 2KCl(aq) + 2H2O(l)

Net ionic equation:

Ca2+(aq) + C2O42-(aq) + H2O(l) >> CaC2O4*H2O(s)

A. Precipitation of CaC2O4*H2O from the salt mixture

Mass of Beaker (g) 161.54

Mass of beaker and salt mixture (g) 162.54

Mass of mixture (g) 1.00

Mass of filter paper (g) 0.57

Mass of filter paper and product after air-dried (g) 0.81

Mass of dried product (g) 0.24

Formula of dried product CaC2O4*H2O ??

B. Determination of limiting reactant

Limiting reactant in salt mixture (complete formula) Ca2+ ??

Excess reactant in salt mixture (complete formula) C2O42- ??

C. Data Analysis

Moles of CaC2O4*H2O precipitated

Moles of limiting reactant in salt mixture

Formula of limiting hydrate

Mass of limiting reactant in salt mixture (g)

Mass of excess reactant in salt mixture (g)

Formula of excess hydrate

Percent limiting reactant in salt mixture

Percent excess reactant in salt mixture

Mass of excess reactant that reacted

Mass of excess reactant unreacted

* show calculations

Explanation / Answer

Formula of dried product CaC2O4*H2O ??

The dried product does not contain water. So, the dried product has formula - CaC2O4

Please provide the concentration or mass or volume of the salts taken to calculate the limiting and exceesive reagents and further the moles.

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