The neutralization of an acid with a base yields a salt (and usually water) in a
ID: 933826 • Letter: T
Question
The neutralization of an acid with a base yields a salt (and usually water) in aqueous solution.
A) Calculate the pH when 51.0mL of 0.284M hydrobromic acid is mixed with 51.0mL of .284M sodium hydroxide at 25C.
The neutralization of an acid with a base yields a salt (and usually water) in aqueous solution. A) Calculate the pH when 51.0mL of 0.284M hydrobromic acid is mixed with 51.0mL of .284M sodium hydroxide at 25C. B)Calculate the pH when 51.0mL of .284M of a certain monoprotic weak acid, HA, is mixed with 51.0mL of .284 sodium hydroxide at 25C. For HA, Ka is 1.1x10-5.Explanation / Answer
A) both HBr and NaOH are strong acid and base, respectively.
since equal volumes of acid and base are mixed here,
pH of solution after mixing = 7.0
B) All of HA is neutralized by NaOH added
[A-] formed = 0.284 M x 51 ml/102 ml = 0.142 M
A- + H2O <==> HA + OH-
let x amount of salt is hydrolyzed
Kb = Kw/Ka = [HA][OH-]/[A-]
1 x 10^-14/1.1 x 10^-5 = x^2/0.142
x = [OH-] = 1.14 x 10^-5 M
pOH = -log[OH-] = -log(1.14 x 10^-5) = 4.94
pH = 14 - pOH = 14 - 4.94 = 9.06
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