The Solubility of AB(s) in a 1.000-M solution of C(aq) is found to be 0.102M. Wh

Question

The Solubility of AB(s) in a 1.000-M solution of C(aq) is found to be 0.102M. What is the Ksp of AB?

The Kf below is correct, I just cant get the Ksp

The generic metal A forms an insoluble salt AB(s) and a complex AC5(aq). The equilibrium concentrations in a solution of ACs were found to be (A] = 0.100 M, [C] = 0.0230 M, and (AC5] = 0.100 M. Determine the formation constant, Kf, of AC5, Kf = 1.55 x 10^8 The solubility of AB(s) in a 1.000-M solution of C(aq) is found to be 0.102 M What is the Ksp of AB? Number Ksp = Number .010 If you sum the chemical equations associated with Kf, and Ksp, you arrive at the chemical equation for the solubility of AB(s) in C(aq). Thus, K for the solubility of AB(S) fl C(aq) is equal to Kf x ksp.

Explanation / Answer

1.02 x 10-3

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