Question 4 Calculate the number of grams of solute in 500.0 mL of 0.159 M KOH. 1
ID: 933288 • Letter: Q
Question
Question 4
Calculate the number of grams of solute in 500.0 mL of 0.159 M KOH.
176
1.42
4.46 × 103
4.46
1.42 × 10-3
Question 7
What is the molarity of a NaOH solution if 15.5 mL of a 0.220 M H2SO4 solution is required to neutralize a 25.0-mL sample of the NaOH solution?
0.273
0.355
0.710
42.6
0.136
2 points
Question 8
1.50
0.666
65.0
43.3
97.5
2 points
Question 9
2.99
0.124
3.34 × 104
0.0644
33.4
176
1.42
4.46 × 103
4.46
1.42 × 10-3
Question 7
What is the molarity of a NaOH solution if 15.5 mL of a 0.220 M H2SO4 solution is required to neutralize a 25.0-mL sample of the NaOH solution?
0.273
0.355
0.710
42.6
0.136
2 points
Question 8
Automotive air bags inflate when sodium azide decomposes explosively to its constituent elements:
2NaN3 (s) 2Na (s) + 3N2 (g)
How many grams of sodium azide are required to produce 28.0 g of nitrogen?
1.50
0.666
65.0
43.3
97.5
2 points
Question 9
The density of air under ordinary conditions at 25 °C is 1.19 g/L. How many kilograms of air are in a room that measures and has an 10.0 ft ceiling?
2.99
0.124
3.34 × 104
0.0644
33.4
Explanation / Answer
4. Concentration,C = No. Of moles of solute,n / Volume of solute in lt,V
0.159 M = n / 0.5 lt
n = 0.0795 moles.
No. Of grams of solute = n * Molar mass of KOH
= 0.0795 * 56.1056
= 4.46 g
7. M1 = Molarity of H2SO4 = 0.220M
V1 = Volume of H2SO4 = 15.5 ml
M2 =Molarity of NaOH = ?
V2 = Volume of NaOH = 25 ml
We know that M1V1 = M2V2
0.220 * 15.5 = M2 * 25
M2 = 0.136 M
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