Write the chemical equation for the following reactions and mention the type: A
ID: 933237 • Letter: W
Question
Write the chemical equation for the following reactions and mention the type: A sample of 0.556 g of an compound containing the bromide ion (Br^-) is dissolved in water and with excess of AgNO3. If the mass of the AgBr precipitate that forms g. What is the percentage by mass of Br in the original compound?? Define the following terms: Boy les law Displacemeat reaction What is the mass of magnesium chloride resulted by the reaction between hydrochloric acid and magnesium, if the volume was 540 ml, pressure 520 mmHg, and temperature 455 "F"? A sample of carbon monoxide gas occupies in 3.25 Litres at 130 Calculate the resulted temperature at which the gas will occupy 800.06 ml the pressure remains unchanged? At STP conditions, 788.89 ml of a gas weighs 0.567 g. Calculate the mass of the gas?Explanation / Answer
8.2HNO3 + Ca(OH)2 ---> Ca(NO3)2 + 2H2O
Pb(NO3)2 + 2AgCl ----> PbCl2 +2 AgNO3
9. Unknown + AgNO3 ----> AgBr
no of moles of AgBr = 0.689/188 = 0.00366 moles of AgBr
no of moles of Br- = 0.00366 moles
mass of Br - = 0.00366*80 = 0.2928gm
percentage of Br- = 0.2929*100/0.556 = 52.6%
10. At constant tempeture given mass of a gas volume is inversly proportional to its volume is called Boyle's law.
Displacement reaction: chemical reaction in which a more reactive element displaces aless reactve element from its compoud.
11. Mg + 2HCl ----> MgCl2 +H2
PV = nRT
n= W/M
PV = WRT/M
P = 520mmhg = 520/760 =,0.68atm
V = 0.54L
M = 95.2
T = 455F0 = 508.15K
W = PVM/RT
= 0.68*0.54*95.2/0.0821*508.15 = 34.95/41.7 = 0.84gm
12. initial
volume V1 = 3.25L
tempereture T1 = 327.7K
Final
V2 = 0.80006 L
T2 =
V1/T1 = V2/T2
T2 = V2T1/V1 = 0.80006*327.7/3.25 = 80.6K
13. STP conditions
Temperature T = 273K
pressure P = 1 atm
volume V = 0.7889L
mass W = 0.567g
PV = nRT
n = W/M
PV = WRT/M
M = WRT/PV
= 0.567*0.0821*273/1*0.7889 = 16
molar mass of gas is 16g/mole
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