Define the following terms: Homogenous mixture Empirical formula Cathode ray Exp

Question

Define the following terms: Homogenous mixture Empirical formula Cathode ray Explain the state of matter and what are the difference between compound and mixture with examples? If the temperature was 325.5 degree C then what is the temperature in degree F and K, try to select the right option from below: Is this sentence correct or not: The electron has a charge and it's has no mass than other atom contents? Write the chemical formula for the following compounds: Calculate the number of grams for AlCl_3 resulted when hydrochloric acid reacted with aluminum hydroxide, suppose the amount of aluminum hydroxide is 45.267g? How many molecules in the product compound produced by the equation below, use the data given (5.0 ml, and 1.27 g/ml)? 2NH_3 + H_3PO_4 rightarrow (NH_4)_2HPO_4

Explanation / Answer

Homogeneous mixture: A mixture which has uniform composition and properties throughout.For example air is a homogeneous mixture of gases(N2 and O2). Salt solution is homogeneous mixture salt uniformly distributed throghout in the solution.

Empirical formula: A formula which gives simplest whole number ratio is called Empirical formula.

Cthode ray: An electron emitted from the cathode of an electrical discharge tube, such as a cathode ray tube

Matter can be classified into three state. They are solid, liquid and gas.

Compound: Compound are pure substances. They are made up of two or more elements combined chemically.

Mixture: Mixtures are impure substances. They are made up of two or more substances mixed physically.

3. 325.5C0

325.5 + 273 = 598.5K

F = 9/5 C + 32

= 9/5*325.5 + 32 = 617.9 F0 >>>>>>>1

4. correct       symbol -1 e0

5. 1) HF 2) N2O4 3) SrNO3 .4H2O

6 Al(OH)3 + 3HCl ---> AlCl3 + 3H2O

1 mole of Al(OH)3 react with HCl to form 1 mole of AlCl3

78gm of AlCl3 react with HCl to form 133.4gm og AlCl3

45.267 gm of Al(OH)3 react with to form = 133.4 *45.267/78 = 77. 41gm of AlCl3

7. mass of( NH4)2HPO4 is volume * density = 5*1.27 = 6.35gm

132g of ( NH4)2HPO4 contains 6.023*1023 molecules

6.35gm of ( NH4)2HPO4 contains 6.023*1023 *6.35/132 = 2.9*1022 molecules

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