Question
Hi everybody,can you help me for problem 1 in the top of attach.Thank for help!
Update: I was edit my question. I moved it back to engineering!
The elementary reversible reaction A+B 2C occurs in the liquid phase in an isothermal CSTR. A stream containing equimolar amounts of A and B in a solvent enters the reactor, and the conversion of A is measured to be 60% The equilibrium conversion of A under the same inlet conditions is known to be 80%. The gas phase, irreversible reaction A + 2B rightarrow C takes place in an isothermal. packed bed reactor. The feed contains 25% A and 75% B (in mole) at 2 bar an inlet volumetric (low rate is 10 L/min. and the outlet volumetric flow rate is the same. Tie conversion of A is 70%. Estimate the outlet pressure. The irreversible gas phase reaction is earned out in a PBR. The reaction is non-clemcntary in that it is first order in A and zero order in B The feed is equal molar in A and B and the pressure at the entrance is 10 atm and rise pressure at the exit is 2 atm. The gas phase irreversible reaction is carried out isothermally in a PBR The reaction is zero order. The entering temperature is 400 K. and the entering pressure is 10 aim. The flow is turbulent. For a 10 kg PBR with a pressure drop parameter a = 0.01 kg^-1, the exit conversion was found to be 0.4. What catalyst w eight of the PBR will you require if you need an exit conversion of 0.8. assuming that the particle diameter is decreased by a factor of 2 so that the pressure drop parameter is now increased to 0.02? Assume all other operating conditions arc the same as for the base case (i.e W = 10 kg). For the fixed inlet pressure of 10 atm, will the volumetric flow rate v, (dm^3/s), be greater, smaller, or remain the same when the particle diameter is decreased by a factor of 2?
Explanation / Answer
Hi everybody,can you help me for problem 1 in the top of attach.Thank for help!
