Real gases are those that A 2.00-L glass soda bottle filled only with air is tig
ID: 932289 • Letter: R
Question
Real gases are those that A 2.00-L glass soda bottle filled only with air is tightly capped at 18 degree C and 718.0 mmHg. If the bottle is placed in water at 71 degree C, what is the pressure in the bottle? An unknown gaseous hydrocarbon contains 85.63% C. Its density is 1.524 g/L at 0.665 atm and 373 K. What is the molecular formula of the gas? Carbon monoxide reacts with oxygen to form carbon dioxide. In a 1.00 L flask, 4.30 atm of CO reacts with 2.50 atm of O_2. Assuming that the temperature remains constant, what is the final pressure in the flask? Equal volumes of propane. C_3H_3,. and carbon monoxide. CO, at the same temperature and pressure have the same The density of a gas is 3.48 g/L at STP. What is its molar mass?Explanation / Answer
21) we know that
PV = nRT
here volume of bottle remains same
so
P / T = constant
at two conditions
P1/T1 = P2 / T2
so
718 / 291 = P2 / 344
P2 = 849 mm Hg
so
the answer is b) 849 mm Hg
23)
PV = nRT
PV = mRT / M
PM = ( m / V) RT
PM = dRT
0.665 x M = 1.524 x 0.0821 x 373
M = 70
so
the molar mass is 70
let hydrocarbon be CaHb
then
12a + b = 70
now
12a / 70 = 0.8563
a = 5
so
b = 10
so
C5H10
the answer is d) C5H10
25)
2C0 + 02 --> 2 C02
for C0
PV = nRT
4.3 x 1 = n x 0.0821 x 298
n = 0.1757
moles of C0 = 0.1757
moles of 02 = 2.5 / 0.0821 x 298
moles of 02 = 0.1022
now
2C0 + 02 --> 2 C02
moles of 02 reacted = 0.5 x moles of C0
moles of 02 reacted = 0.08785
moles of 02 remaining = 0.1022 - 0.08785 = 0.01435
moles of C0 remaining = 0
moles of C02 formed = moles of C0 reacted = 0.1757
now
finally
total moles = 0.1757 + 0.01435
total moles = 0.19005
now
PV = nRT
P x 1 = 0.19005 x 0.0821 x 298
P = 4.65
so
final pressure is 4.65 atm
answer is d) 4.65 atm
27)
PV = nRT
given
volume are same , pressure and temp are also same
so
both will same moles
so both will have same molecules
so
e) number of molecules
28)
STP conditions are
P = 1 atm
T = 273 K
so
PM = dRT
1 x M = 3.48 x 0.0821 x 273
M = 78
so
the molar mass of the gas is 78 g / mol
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