ezto.mheducation.com in Connect. CHEM 102 Fall 2015: CHEM 102 Fall 2015 Lec02 CH
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ezto.mheducation.com in Connect. CHEM 102 Fall 2015: CHEM 102 Fall 2015 Lec02 CHEMISTRY Chapter 17 Question 3 (of 10) value 10.00 points 1 out of 5 attempts Be sure to answer all parts. Assistance lmal 2 Check My Work The molar heats of fusion and vaporization of a certain substance are 2.93 kJ/mol and 8.25 kJ/mol, and its melting point and boiling point are- 162C and 138°C, respectively Calculate the entropy changes for fusion (solid to liquid) and vaporization (liquid to gas ASfus= View Hint Show Me Guided Solution Print Question Help Report a Problem J/K mol J/K.mol vap ReferencesExplanation / Answer
Sfusion = Hfusion/Tmpt = (2.93x1000)/111.15 =26.36 J/Mol.k
Svap = Hvap/TBpt = (8.25x1000)/135.15 = 61.04J/Mol.k
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