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ezto.mheducation.com in Connect. CHEM 102 Fall 2015: CHEM 102 Fall 2015 Lec02 CH

ID: 929399 • Letter: E

Question

ezto.mheducation.com in Connect. CHEM 102 Fall 2015: CHEM 102 Fall 2015 Lec02 CHEMISTRY Chapter 17 Question 3 (of 10) value 10.00 points 1 out of 5 attempts Be sure to answer all parts. Assistance lmal 2 Check My Work The molar heats of fusion and vaporization of a certain substance are 2.93 kJ/mol and 8.25 kJ/mol, and its melting point and boiling point are- 162C and 138°C, respectively Calculate the entropy changes for fusion (solid to liquid) and vaporization (liquid to gas ASfus= View Hint Show Me Guided Solution Print Question Help Report a Problem J/K mol J/K.mol vap References

Explanation / Answer

Sfusion = Hfusion/Tmpt    = (2.93x1000)/111.15 =26.36 J/Mol.k

Svap = Hvap/TBpt    = (8.25x1000)/135.15 = 61.04J/Mol.k