a 25.0 g sample of a metal at 98.0 Degrees C is placed in 50.0 g of water at 18.
ID: 929179 • Letter: A
Question
a 25.0 g sample of a metal at 98.0 Degrees C is placed in 50.0 g of water at 18.0 C. If the final temperature of the alloy and water is 27.4 C what is the specific heat of the metal?a 25.0 g sample of a metal at 98.0 Degrees C is placed in 50.0 g of water at 18.0 C. If the final temperature of the alloy and water is 27.4 C what is the specific heat of the metal?
a 25.0 g sample of a metal at 98.0 Degrees C is placed in 50.0 g of water at 18.0 C. If the final temperature of the alloy and water is 27.4 C what is the specific heat of the metal?
Explanation / Answer
use:
Heat lost be metal = heat gained by water
m1*C1*delta T1 = m2*C2*delta T2
25*C1*(98-27.4) = 50*4.186*(27.4-18)
C1= 1.115 J/g-oC
Answer: 1.115 J/g-oC
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