PLEASE SHOW ANSWERS clearly FOR ALL 1. ) In reaction 2NO + O2 the %yield is only

Question

PLEASE SHOW ANSWERS clearly FOR ALL

1. ) In reaction 2NO + O2 the %yield is only 80.2%. To produce 25.0g of NO2 how many grams of O2 are required?

       2 .) BaCl2 + Na2CO3 - BaCO3 +2NaCl. A) If 3.50g of BaCl2 is added to 2.00g of Na2CO3, which is the limiting reagent? B) How many grams of NaCl theoretically can be produced? C) If the reaction produced 1.70g of NaCl, what is the % yield? D) How many grams of excess reagent remains? Please show working

a)

b)

c)

d)

3).The photosynthesis reaction is 6CO2 (g) + 6H2O (g) (Arrow) C6H12O6(s) + 6O2 (g). If the reaction requires 2.82 x 10^3 kJ/ mole of C6H12O6 formed:

a.) How many grams of C6H12O6 can be produced from 4.20 x 10^4 kJ?

b). How much energy is required to produced 250g of C6H12O6?

c.)How many liters (at STP) of O2 are produced with 250g of C6H12O6?

Explanation / Answer

1.    2NO + O2 ---> 2NO2

nO of mol of NO2 = 25 / 46 = 0.5435 mol

so that, 80% = 0.5435 mol

100% = 0.5435*100/80 = 0.679375 mol

No of mol of O2 required = 0.679375/2 = 0.34 mol

mass of O2 required   = 0.34*32 = 10.88 grams.

2. BaCl2 + Na2CO3 ----> BaCO3 +2NaCl

A) No of mol of BaCl2 = 3.5/208.2330 = 0.017 mol

No of mol of Na2co3   = 2/105.9888 = 0.019 mol

limiting reagents is BaCl2

B) No of mol of Nacl produced = 0.017*2 mol

mass of Nacl produced = 0.017*2*58.5 = 1.989 grams.

C) percentyield = practical yield / theoretical yield*100

                = (1.7/1.989*100) = 85.47%

d) excess reagentremains = (0.019-0.017)*105.9888 = 0.212 grams.

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