The percent by mass of bicarbonate (HCO3-) in a certain Alka-Seltzer product is

Question

The percent by mass of bicarbonate (HCO3-) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 generated (in mL) at 37 degrees C and 1.00 atm if a person were to accidentally ingest a 3.71-g tablet without following instructions. ( hint: the reaction occurs between HCO3- and HCL acid in the stomach.)
(ENTER ANSWER IN SCIENTIFIC NOTATION) The percent by mass of bicarbonate (HCO3-) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 generated (in mL) at 37 degrees C and 1.00 atm if a person were to accidentally ingest a 3.71-g tablet without following instructions. ( hint: the reaction occurs between HCO3- and HCL acid in the stomach.)
(ENTER ANSWER IN SCIENTIFIC NOTATION)
(ENTER ANSWER IN SCIENTIFIC NOTATION)

Explanation / Answer

HCO3- + HCl -> H2O +Cl- + CO2

mass of bicarbonate = 0.325*3.71

=1.2 grams

so moles of bicarbinate= moles of CO2 = 1.2/61

=0.01967 moles

using the ideal gas law,

PV=nRT,

1*v=0.01967*(1/12)*(273+37)

or v=0.508 L

=5.08*10^2 mL

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