adiation, including the radi- You can remember the colors of visible light LIDIO

Question

adiation, including the radi- You can remember the colors of visible light LIDIO IgRl. As you know, visible light really consists of a spec in order of deoessing wavelength, by the famou ranging from red light at the long-wavelength end of the spec mnemonic phrasc ROY G BIV trum to violet num of ciolet light at the short-wavelength end (Figure 7.3), Visible light is, nd ors, r to violet light at volt light a which stands ength end (Figure 7.3). Visible light is, for red, oranelur, indig- and violet. 1022 1020101014 1012 102 102010 10 1020 10 102 1024 1022 1010 10 10 10 10 H IR Microwave FM AM Radio waves 10-6 10-4 1012 1010-5 106 14 10-12 10006 10 102 10 102 0110m Visible spectrum Figure 7.3 The electromagnetic spee trum. Visible light (enlarged portion) i a small part of the entire spectrum. Th diation's energy increases from the rad wave end of the spectrum (low freque v, and long wavelength, A) to the yra Chigh frequency and short wavelengtl 600 700 400 500 wavelength (nanometers) Energy

Explanation / Answer

Solutuion :-

21 a) microwave has the less energy than the x-ray because as the wavelength increases then energy decreases.

b) Red light has the higher frequency than the radar because wavelength and frequency are inversely proportional

c) Infra red light has the higher wavelength than the UV light.

Green light has wavelength 5.0*10^2 nm

5.0*10^2 nm * 1 m / 1*10^9 nm = 5.00*10^-7 m

Lets calculate the frequency of the green light

Frequency (f) = c/ wavelength                       ( C = speed of light = 3*10^8 m/s)

                        = 3*10^8 m s-1 / 5.00*10^-7 m

                        = 6.00*10^14 s-1

So the frequency of the light = 6.00*10^14 s-1

Now lets calculate the energy of the 1 photon

E= h* frequency

E= 6.626*10^-34 J .s * 6.00*10^14 s-1

E= 3.98*10^-19 J / photon

Now lets calculate the energy of the 1.00 mol photon

Therefore

3.98*10^-19 J per photon * 6.02*10^23 photon = 2.39*10^5 J

So the energy of the 1.00 mol photon = 2.39*10^5 J

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