A possibility to determine the amount of Ca^2+ ions in a solution is by forming

Question

A possibility to determine the amount of Ca^2+ ions in a solution is by forming a precipitate with the Oxalate Ion. There for a precipitate is formed by mixing the solution with the unknown amount of Ca^2+ with an excess of an Oxalat solution. Don't to spend all the mixture (1 L in whole) only 50 mL are used. Calculate the amount of Ca^2+ ions (in grams) which were present in the whole 1 L mixture, if 410.0 mg precipitate were measured after filtration and 100.1 mg were found after drying. Use for your calculations the following reaction of the forming and the drying of the precipitate: Formation of the precipitate: Ca^2+ (aq) + C_2 _4^2 (aq) rightarrow CaC_2 O_4 xH_2 O_(s) Dehydration during drying: CaC_2 O_4 xH_2 O_(s) rightarrow CaC_2 O_4 1 H_2 O_(s) + x - 1H_2O_(g)

Explanation / Answer

molar mass of CaC2O4.H2O = 40 + 24+64+2+16

=146

so, moles of CaC2O4.xH2O=0.1001/146

so mass of Ca2+ present in 1 liter on the solution = (1000/50)*(0.1001/146)

=0.013 grams

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