7. Tetraphosphorous trioxide has which molecular formula? A. 4P3O B. P 3 O 4 C.
ID: 921157 • Letter: 7
Question
7. Tetraphosphorous trioxide has which molecular formula?
A. 4P3O
B. P3O4
C. P4O4
D. P4O3
9. What is the mass of a metal that displaces 1.296 mL of water and has a density of 9.43 g/cm3?
A. 0.1374 g
B. 0.137 g
C. 12.2 g
D. 12.22 g
10. Your protocol requires you measure 100 mL of a solution. The most appropriate vessel to use is
A. A 100 mL beaker
B. A 500 mL graduated cylinder
C. A 100 mL graduated cyclinder
D. A 250 mL beaker
11. How many molecules are in 42 moles of nitrogen gas?
A. 588 molecules
B. 1176 molecules
C. 6.8 x 10-23 molecules
D. 2.5 x 1025 molecules
12. How many grams are in 42 moles of nitrogen gas?
A. 588 g
B. 1176 g
C. 6.8 x 10-23 molecules
D. 2.5 x 1025 molecules
For questions 13-14, use the information provided below from the experiment Identification of an Unknown. The molecular masses and reactions are provided for you.
NaHCO3 KHCO3 Na2CO3 K2CO3 NaCl KCl
84.01 g/mol 100.12 g/mol 105.99 g/mol 138.21 g/mol 58.44 g/mol 74.55g/mol
2 NaHCO3 (s) à Na2CO3 (s) + H2O (g) + CO2 (g) (Reaction 1)
Na2CO3 (s) +2HCl (aq) à 2NaCl (s) + H2O (l) + CO2 (g) (Reaction 2)
13. Brad starts with 0.652 g of unknown. How much mass should he have after the first heating step if his unknown
was NaHCO3?
A. 0.411 g Na2CO3
B. 0.326 g Na2CO3
C. 0.822 g Na2CO3
D. 0.00402 g Na2CO3
If Brad has a final mass of 0.270 g at the end of the experiment (after the 2nd heating), what is his percent yield
of the final salt? (Assuming he starts with 0.652 g of NaHCO3).
A. 40% B.60% C. 80% D. 86%
Explanation / Answer
7. D. P4O3
9. mass = density*volume = 9.43*1.296 = 12.22 grams
D. 12.22 g
10. C. A 100 mL graduated cyclinder
11. 1 mole = 6.023*10^23 molecules
42 mole = 42*6.023*10^23 = 2.53*10^25 molecules .
D.2.5 x 1025 molecules
12. mass of 42 mole N2 = 42*28 = 1176 gram
B. 1176 grams
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.