The following two half-reactions occur in a voltaic cell: Ni(s)Cu2+(aq) + 2 eNi2

Question

The following two half-reactions occur in a voltaic cell:

Ni(s)Cu2+(aq) + 2 eNi2+(aq) + 2 eCu(s) (electrode=Ni)(electrode=Cu)

Which one of the following descriptions most accurately describes what is occurring in the half cell containing the Cu electrode and Cu2+(aq) solution?

The electrode is gaining mass and cations from the salt bridge are flowing into the half cell. The electrode is losing mass and cations from the salt bridge are flowing into the half cell. The electrode is losing mass and anions from the salt bridge are flowing into the half cell. The electrode is gaining mass and anions from the salt bridge are flowing into the half cell.

Explanation / Answer

the two half reactions are

Ni(s) ----> Ni+2 (aq) + 2e-

and

Cu+2 (aq) + 2e- ----. Cu (s)

now

consider the half cell with copper electrode

we can see that

Cu+2 ions are flowing into the half cell and get deposited

So

the mass of the electrode increases

so

the correct answer is

The electrode is gaining mass and cations from the salt bridge are flowing into the half cell

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