neutralization is my experiment. I have a tutor and he didn\'t explain very well
ID: 919901 • Letter: N
Question
neutralization is my experiment. I have a tutor and he didn't explain very well when to use which formula. I'll give my samples of experiments then ask what the questions are. I'll give my answer for one, but without a formula I'm unable to figure the rest. I want to be able to apply it on my own when I'm quizzed on it. so please show step by step.
My data:
mass of flask : 78.9796 g
mass of empty flask :77.3805 g
mass of KHP: 1.1219 g
final Buret reading: 31.5 ml
initial Buret reading: 50.0 ml
volume of base used:18.5 ml
(should I use sig figs? )
1)moles of acid (KHP, molar mass=204.2)
( my answer I wrote is 0.00549 mols because I figured 1.1219g/204.2=0.00549 Mol , is that right? did I figure correctly? next parts are harder for me.
2)moles of base used to neutralize the above number of moles of acid.
3)molarity of base (NaOH)
4)average molarity of base.
now she wrote moles of acid =moles of base, does that mean my base is 0.00549? it's all part of one huge answer. thank u for your help.
Explanation / Answer
From the given data -
Mass of KHP = mass of flask - mass of empty flask = 78.9796 g - 77.3805 g = 1.5991 g ( But in data given 1.1219 g)
Number of mols of KHP = mass of KHP/Molar mass = 1.5991 g / 204.22 g/mol = 0.00783 mole.Thus, the same number of mols of base must be used for neutralization from balanced equation.
Therefore, number of mols of NaOH = 0.00783 mole
Volume of base from burett = 18.5 mL
Hence, Molarity of base = number of mols / Volume in L
= (0.00783 mol / 18.5 mL)*1000 = 0.423 mol/L
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