Alcohol by volume (abbreviated as ABV, or Alc/Vol) is a standard measure of how
ID: 918993 • Letter: A
Question
Alcohol by volume (abbreviated as ABV, or Alc/Vol) is a standard measure of how much alcohol (ethanol) is contanied in an alcoholic beverage (expressed as a percentage of totoal volume) you order a bottle of wine (450.0 ml), whose concentration is 10.6%. Convert this ABV to Molarity (M), Molality (m), and mole fraction (X). This wine has a density 0.95 g/ml.
Find:
A) Grams of ethanol
B) Moles of ethanol
C) Grams of water
D) Kilograms of water
E) Moles of water
F) Molarity (M)
G) Molality (m)
H) Mole fraction of ethanol
Explanation / Answer
Alcohol by volume (abbreviated as ABV, or Alc/Vol) is a standard measure of how much alcohol (ethanol) is contanied in an alcoholic beverage (expressed as a percentage of totoal volume) you order a bottle of wine (450.0 ml), whose concentration is 10.6%. Convert this ABV to Molarity (M), Molality (m), and mole fraction (X). This wine has a density 0.95 g/ml.
Find:
Lets first calculate the volume ethanol
Volume of ethanol = 10.6 % * 450.0 ml / 100 ml = 47.7 ml
So the volume of water = 450.0 – 47.7 ml = 402.3 ml
Mass of solution = 450.0 ml * 0.95 g per ml = 427.5 g
So the mass of water = 402.3 g because density of water is 1 g per ml
Mass of ethanol = 427.5 g – 402.3 g = 25.2 g
A) Grams of ethanol = 25.2 g
B) Moles of ethanol = mass / molar mass
= 25.2 g / 46.06844 g per mol
= 0.5470 mol ethanol
C) Grams of water = 402.3 g
D) Kilograms of water = 0.4023 kg
E) Moles of water = mass / molar mass
= 402.3 g / 18.0148 g per mol
= 22.33 mol water
F) Molarity (M) = moles of ethanol / volume in liter
= 0.5470 mol / 0.450 L
= 1.216 M
G) Molality (m) = moles / kg solvent
= 0.5470 mol / 0.4023 kg
= 1.360 m
H) Mole fraction of ethanol = moles of ethanol / total moles
= 0.5470 mol / (0.5470 mol + 22.33 mol )
= 0.02391
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