The electron configuration of a manganese ion (Z = 25) is [Ar]3d^3. What is the

Question

The electron configuration of a manganese ion (Z = 25) is [Ar]3d^3. What is the change on this ion? +7 +5 +4 +3 +2 Compared with the atomic radius of oxygen (Z = 8). The atomic radius of sulfur (z = 16) is larger because the quantum number increases. smaller because the atomic number (nuclcear charge) increases. Smaller because the quantum number increases. large because the quantum number increases. about the same because in both cases, the nuclear charge equals the number of eletcrons. Which arrangement is in the correct order of decreasing radii?

Explanation / Answer

39)

shortest wavleenght ---> highest energy

therefore choose the 1/nf^2 - 1/ni^2 which has the highest difference which is from 3 to 1

40)

if n = 3 then

number of orbitals (l) are l = 3-1 = 2

41)

if 4f then n = 4 and f = 3; (s,p,d,f, --> (0,1,2,3)) therefore l = 3

n = 4 and l = 3

42)

a - d orbital

b - d orbital

c - d orbital

d - p orbital, therefore choose this one

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