Zn reacts with HCl to from ZnCl3 how many moles of HCl are required to react sto

Question

Zn reacts with HCl to from ZnCl3 how many moles of HCl are required to react stoichiometrically with 1.00 g of Zn?

My answer was .0306

The number of moles of HCl in an aqueous hydrochloric acid solution can be determined as follows

moles=(concentration in M units) (Volume in liters)

Using this method, which of the follow is correct for the Zn+HCl reaction?

1) HCl reagent was added in excess 2) HCl was the limiting reagent 3)Zn and HCl were added in the stoichiometric amounts 4)The reaction stoichiometry of Zn and HCl cannot be determinded

Which of the following statements is correct?

1)It is essential that there be metal left over after the reaction runs to completion so all the HCl is consumed

2) It is essential that there be HCl left over after the reaction runs to completion so all the metal is consumed

3) It is essential that HCl and the metal are reacted in a stoichiometric ratio

Explanation / Answer

Zn + 2HCl --> ZnCl2 + H2

m = 1 g of Zn

MW Zn = 65.38

mol = mass/MW = 1 /65.38 = 0.015295197 mol of Zn

therefore, we require 2 times that amount (2:1 ratio)

2*0.015295197 = 0.03059 mol of HCl are required

as stated before:

3)Zn and HCl were added in the stoichiometric amounts

And once again,

3) It is essential that HCl and the metal are reacted in a stoichiometric ratio

Related Questions

Navigate

• Browse (All)
• Browse Z
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.