2N_20_5= 4no_2+O_2 Rate = k[N_2O_5] k = 4.0 Times 10^-3 (1/s) at certain tempera

Question

2N_20_5= 4no_2+O_2 Rate = k[N_2O_5] k = 4.0 Times 10^-3 (1/s) at certain temperature What is half life t_1/2 and how long does it take for N_2O_5 concentration io drop to 1/3 of its original value? If the reaction is second order and initial concentration of N_2O_5 is 0.01, what is half-life t_1/2 and how long does it take for N_2O_5 concentration to drop to 1/3 of its original value? If the reaction is zero order and initial concentration of N_2O_5 is 0.01, what is half-life t_1/3 and how long does it take for N_2O_5 concentration to drop to 1/3 of its original value?

Explanation / Answer

From the equation given in the question:

2N2O5 = 4NO2+O2

rate = K[N2O5]

K = 4.0*10-3(persec)

It is a first order reaction as unit of K is time inverse.

the value of half life t1/2 = 0.693/K

= 0.693/4.0*10^-3

= 173.25 Seconds

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