Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

L Welcom e, John-Blackbox / te Southeastern Oklahoma Sxe The Equation For ATP Hy

ID: 914569 • Letter: L

Question

L Welcom e, John-Blackbox / te Southeastern Oklahoma Sxe The Equation For ATP Hycx -) Dwww.saplinglearning.com/ib.scms/mod/ibis/view.php?id=2388295 0 Yo Gotti-Down In The + × Austin Jump to.. Logout sapling learning Sapling Learning My Assignment Southeastern Oklahoma State University-BIOUCHEM 4193-Spring16-PAIVA Activities and Due Dates Ch13 Bioenergetics; Biochemical Reactions Resources 1/27/2016 06:00 PM > 957/1001/21/2016 07:30 PM Assignment Information Available From 1/16/2016 04:00 PMM Due Date: Points Possible Grade Category: Graded Description: Policies: Gradebook #AttemptsScore Print Calculator Periadic Table 95 Question 11 of 32 1/27/2016 06:00 PM ATP-> ADP+ P G -30.5 kJ / mol Map 100 (a) Calculate AG for ATP hydrolysis to rank the following conditions from most favorable to least favorable 4 85 sume a temperature of 37.0 C. R 8.315 J(mol- K) ATP hydrolysis most favorable brain: [ATP]-2.6 mM: [ADP] = 0.7 mM: [Pi] = 2.7 mM muscle: [ATP] = 8.1 mM: [ADP] = 0.9 mM: [Pi] = 8.1 mM 98 Homework 100 You can check your answers. You can view solutions when you complete or give up on any question. 100 liver [ATP]-3.4 mM. [ADP]-1.3 mM: [PJ-4.8 mM You can keep trying to answer each question until you get it right or give up. 13 100 ATP hydrolysis least favorable continued below... You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer 100 (b) Calculate 3 for ATP hydrolysis in liver at 18 °C. Use the liver concentrations from part a 100 Help With This Topic Web Help &Videos; Technical Support and Bug Reports 98 G- 1-4.74x 1 | kJ / mol 100 8:29 PM 1/21/2016 I'm Cortana. Ask me anything )

Explanation / Answer

Part (b) dG = dGo + RTlnQ

dGo = -30.5 kJ/mol

R = 8.314 J/K.mol

T = 18 oC = 18 + 273 = 291 K

Q = [ADP][Pi]/[ATP]

Feed values,

dG = -30500 + (8.314 x 291)ln(1.3 x 4.8/3.4) = -29.031 kJ/mol