Write the net ionic equation for the reaction under acidic conditions. I do not

Question

Write the net ionic equation for the reaction under acidic conditions. I do not understand why my answer was incorrect, please help!

In sediments and waterlogged soil, dissolved O2 concentrations are so low that the microorganisms living there must rely on other sources of oxygen for respiration. Some bacteria can extract the oxygen in sulfate ions, reducing the sulfur in them to hydrogen sulfide gas and giving the sediments or soil a distinctive rotten-egg odor a. What is the oxidation number of sulur in these compounds? SO42(aq): Hydrogen is an element that most often forms a +1 ion while oxygen is an element that most often forms a -2 ion. What would these often forms a on. Wha common ions imply about the sulfur ion's charge in the compound. H2S(g): -2 H2S(g): 2 b. Write the net ionic equation for the reaction under acidic conditions (H30) that releases O2 from sulfate and forms hydrogen sulfide gas. Use water as the reactant in the half-reaction that describes the formation of oxygen. so; (aq) + 6H , (aq) H2S(g)+O2(g)+2H2O( Include phases in the balanced chemical equation. Type an open parenthesis "" to add a phase. Phases should not be subscripted. Use the left and right arrow keys to move the cursor out of a superscript or subscript in the module.

Explanation / Answer

Oxidation numbers calculations

SO4^-2 = [x+4*(-2)] = -2

           = x = -2 +8 = +6

Sulfur oxidation state is +6

H2S = [2*(+1) +x] = 0

          x = -2

.....................................................................................................................................................

First half reaction

SO4^-2(aq) + 6H+ (aq) ..............>H2S(g) + O2(g) + 2H2O(l) + 4e-.......................1

Another half reaction

H2O(l) .............>O2 (g)

2H2O(l)............> O2(g) + 4H+

2H2O(l) + 4e- ..............> O2(g) + 4H+ ....................................................2

Add eq1 and eq.2

SO4^-2(aq) + 2H+ (aq) ..............>H2S(g) + 2O2(g)

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