Using standard heats of formation, calculate the standard enthalpy change for th

Question

Using standard heats of formation, calculate the standard enthalpy change for the following reaction:
1) HCL(g) + NH3(g) = NH3CL(s) Answer: kJ
2) NH4CL(aq) = NH3(g) + HCL(aq) Answer: kJ Using standard heats of formation, calculate the standard enthalpy change for the following reaction:
1) HCL(g) + NH3(g) = NH3CL(s) Answer: kJ
2) NH4CL(aq) = NH3(g) + HCL(aq) Answer: kJ Using standard heats of formation, calculate the standard enthalpy change for the following reaction:
1) HCL(g) + NH3(g) = NH3CL(s) Answer: kJ
2) NH4CL(aq) = NH3(g) + HCL(aq) Answer: kJ

Explanation / Answer

1. Standard enthalpy of formation of HCl (g) = -92.3kJ/mol

Standard enthalpy of formation of NH3(g) = -46.2kJ/mol

Standard enthalpy of formation of NH4Cl (g) = -314.4kJ/mol

So, dH reaction = Hproducts - Hreactants

dHreaction = (-314.4kJ/mol) - (-92.3-46.2 kJ/mol) = -175.9kJ/mol

2) Standard enthalpy of formation of NH4Cl (aq) = -300.2kJ/mol

Standard enthalpy of formation of NH3(g) = -46.2kJ/mol

Standard enthalpy of formation of HCl (aq) = -167.2kJ/mol

So, dH reaction = Hproducts - Hreactants

dHreaction = (-46.2-167.2 kJ/mol) - (-300.2 kJ/mol) = 86.8kJ/mol

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