phosphorus trichloride can be prepared by the followin reactin 2P+3Cl2->2PCl3. i
ID: 909114 • Letter: P
Question
phosphorus trichloride can be prepared by the followin reactin 2P+3Cl2->2PCl3. if you begin with 26.3 grams of phosphorus p and 51.8 grams of chlorine what is the limiting reagent How many grams of PCl3 will be formed? How many grams of the excess reagent will be left? phosphorus trichloride can be prepared by the followin reactin 2P+3Cl2->2PCl3. if you begin with 26.3 grams of phosphorus p and 51.8 grams of chlorine what is the limiting reagent How many grams of PCl3 will be formed? How many grams of the excess reagent will be left? phosphorus trichloride can be prepared by the followin reactin 2P+3Cl2->2PCl3. if you begin with 26.3 grams of phosphorus p and 51.8 grams of chlorine what is the limiting reagent How many grams of PCl3 will be formed? How many grams of the excess reagent will be left?Explanation / Answer
2P + 3 Cl2 ---------------> 2PCl3
General 2*30.97=61.95g 3*71=213g 2*137.32=274.64g
Given initial 26.3g 51.8g 0g
After reaction 11.2342g 0g(limiting reagent) 66.79g
61.95g phosphorous requires 213g of Cl2 for complete reaction
26.3g phosphorous requires 26.3*213/61.95 = 90.426g of Chlorine for complete reaction
in this case phosphorous is in excess , so Chlorine is limiting reagent.
213g Cl2 requires 61.95g P
51.8g Cl2 requires 61.95*51.8/213=15.065g of P
Excess P = 26.3 - 15.065 = 11.2342g
213g Cl2 can form 274.64g PCl3
51.8g can form 274.64*51.8/213=66.79g PCl3
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