1) Ethane (a component of natural gas) burns according to the equation: 2 C2H6 +

Question

1) Ethane (a component of natural gas) burns according to the equation:
2 C2H6 + 7 O2 4 CO2 + 6 H2O
a) If one starts with 1 mole of C2H6, how many moles of oxygen (O2) are required to react with it? How many moles of CO2 and H2O are produced?
b) If one starts with 4.3 moles of C2H6, how many moles of O2 are required? How many moles of CO2 and H2O are produced?
c) If one produces 25 moles of CO2 by the above reaction, how many moles of C2H6 were
originally present as reactants?
d) If one starts with 100g of C2H6, how many grams of O2 are required? How many grams of
CO2 are produced? How many grams of H2O?

2. Given the balanced equation:
2 C2H2 + 5 O2 4 CO2 + 2 H2O
a) If one starts with 4 moles of O2, how many moles of C2H2 (acetylene) will react with it? How
many moles of CO2 will be produced? How many moles of H2O will be produced?
b) Starting with 15 moles of C2H2, how many moles of O2 are required to react with it? How
many moles of CO2 will be produced? How many moles of H2O will be produced?
c) Starting with 130g of C2H2, how many grams of O2 are required? How many grams of CO2
are produced? How many grams of H2O are produced?
d) If one produces 360g of CO2, how many grams of C2H2 did one start with? How many grams
of O2 were required? How many grams of water were produced?

Explanation / Answer

2 C2H6 + 7 O2 ---------------------> 4 CO2 + 6 H2O

a) if one starts with 1 mole of C2H6 ,

3/2 oxygen (O2) required to react.

2 moles of CO2 and 3 moles of H2O are produced.

b)

if one starts with 4.3 moles of C2H6 ,

2 mol C2H6 -------------- 7 mol O2

4.3 mol C2H6 -------------- 4.3 x 7 / 2 = 15.05

15.05 moles of O2 required.

for 1 mol ------- 2 mol of CO2 + 3 mol of H2O produced

for 4.3 mol ---------- 8.6 mol of CO2 + 12.9 mol of H2O produced

c)

for 2 mol C2H6 -------------- 4 mol of CO2 produced

for ?? mol C2H6 ------------- 25 mol of CO2 produced

mol of C2H6 present = 25 x 2 / 4 = 12.5

12.5 mol of C2H6 present

d)

moles of C2H6 = mass / molar mass of C2H6 = 100 / 30.069 = 3.326

1 mol C2H6 require ----------- 3/2 mol of O2

3.326 mol C2H6 ------------- 3.326 x 3/2 = 4.989 mol

moles = mass / molar mass

4.989 = mass / 32

mass of O2 required = 159.64 g

for 1 mol ------- 2 mol of CO2 + 3 mol of H2O produced

moles of CO2 and H2O produced for 3.326 mol of C2H6 = 6.652 mol of CO2 + 9.978 mol of H2O

mass of CO2 = mass / molar mass

6.652 = mass / 44

mass of CO2 produced = 292.68 g

mass of H2O produced = 179.6 g

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