Answer the following... a. If the solubility of sodium acetate (Molar mass = 82

Question

Answer the following...

a. If the solubility of sodium acetate (Molar mass = 82 g/mol) is 76 grams per 100 grams of water, which of the following solutions would be considered supersaturated? ___________________________________

b. If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered unsaturated? __________________________________________

c. The solubility of Pb(NO3)2 is 55 grams per 100 g H2O at 20°C. Which term would properly describe a solution where 44 grams of Pb(NO3)2 is added to 100 grams of water at this temperature? _____________

d. We dissolve 2.45 g of sugar in 200.0 g water. What is the mass percent of sugar in the solution? ____________ e. What is the mass percent of a solution prepared by dissolving of solid into of water? ____

f. What is the molarity of a solution prepared by dissolving NaI in 0.250 L? ______

g. Given that you wished to use exactly 0.325 mole of NaCl to prepare a 2.50 M NaCl solution, how many milliliters of solution must you prepare?_________

h. What is the molarity of a solution prepared by dissolving 54.3 g of Ca(NO3)2 into 355 ml of water? ____________

i. A 90.0 g sample of NaOH is dissolved in water and the solution is diluted to give a final volume of 3.00 liters. The molarity of the final solution is ________.

Explanation / Answer

Solubility: (76g / 0.1L) = 760 g/L
760 g/L ÷ 82 g/mol = 9.27 mol/L

8.5 mol ÷ 1 L = 8.5 mol/L
5.5 mol ÷ 0.5 L = 11 mol/L
1.8 mol ÷ 0.3 L = 6 mol/L
1.2 mol ÷ 0.2 L = 6 mol/L

the solubility of 9.27 mol/L.

Molar mass NaCl = 58.4 g/mol

1 liter of H2O weights 1000 g

solubility = 36 / 100 = 0.36

a)1.85 mol x 58.4 g/mol = 108.1 g

108.1 g / 300 g = 0.360

b) 5.8 x 58.4 =338.7 g

338.7 g / 1000 = 0.339 < 0.36 UNSATURATED

c) 3.25 x 58.4 = 189.8 g

189.8 / 500 = 0.380

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