nital buret volume In L Colculate the number of moles of HCl you mixed with the

Question

nital buret volume In L Colculate the number of moles of HCl you mixed with the ontscid tablet Moles HCl added to flask· ,-vio 2 Caloulate the nunber of moles of NoOH you edded to the flack during titration Males NoOH odded to Flask MowV 3. Given that the reaction between Ne0H od Hew many moles of HQ were neutrelized by the NoOH odded to the flask (moles NoOH is calculeted in step 2)? 4 How mony moles of HCl were neutrelized by one antacid tablet (this is the oifference between the initial namber of moles HCl edsed to the flosk from step 1 and the rumber of moles of HCl neutralized by the NoOH from step 3)p . How many moles of HCI can the whole battle of tablets neutradlize? 6. How much does it cost to neutralize 1 mole of HCI with your antacid 10 30213 To %2 60.00m 50,00 mL 56.00m 0.500 0.500 500 0 |C-500 MI CM) -500 MHEI Can) | 0.50 0 a.7 Myacs(M) |0.500 Final Buret |55.83 | u.on

Explanation / Answer

1. moles of HCl = 0.5 mol/L * 0.05 L = 0.025 moles of HCl

2. moles of NaOH = 0.5 mol/L x 0.01483 L = 0.0074 moles of NaOH

3. The reaction is the following:

NaOH + HCl --------> NaCl + H2O

0.0074 0.025

0 0.025 - 0.0074

moles neutralized: 0.025 - 0.0074 = 0.017585 moles of HCl neutralized.

4. moles of HCl neutralized by antiacid: 0.025 - 0.017585 = 0.007415 moles

This is for 1 tablet.

5. if a bottle has 150 tables, then:

150 x 0.007415 = 1.11225 moles

The last question I don't understand it very well. You mean price cost? if this the case, you need to put the price of the bottle.

Do the same calculations with data of table 2 and tablet 3, and you'll get similar results.

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