lace helllas a subscrlpt. Do not stack charges and subscripts. To add a charge t

Question

lace helllas a subscrlpt. Do not stack charges and subscripts. To add a charge to an ion with a subscript, f charges and subscripts. To add a charge to an ion with a subscript, first enter the For example, to type SO, For example, to type SO4 start by typing S04 .Then use the arrow key to arrow over before start by typing sos . Then use the arrow key to arrow over bef superscript with the charge. If you make a formatting error, you will see an message such as "Check your placement of subscripts a superscripts." or "There is an error in your submission. Make sure you have formatted it properly." You credit, but the answer will need to be edited and resubmitted. Part B What is the net ionic equation of the reaction of ZnCl2 with NaOH? Express your answer as a chemical equation. Zn2 (aq) 20H (a) >Zn(OH)2 (s) Hints My Answers Give Up Review Part All attempts used; correct answer displayed Part C

Explanation / Answer

6B)

The reaction:

ZnCl2 + NaOH

Must react to form Zn(OH)2

ZnCl2 + 2NaOH -- > 2NaCl + Zn(OH)2

Split this into ions

Zn+2(aq) + 2Cl-(aq) + 2Na+(aq) + 2OH-(aq) --> Zn(OH)2(s) + 2Na+(aq) + 2Cl-(aq)

Take out spectator ions

Zn+2(aq) + 2Cl-(aq) + 2Na+(aq) + 2OH-(aq) --> Zn(OH)2(s) + 2Na+(aq) + 2Cl-(aq)

Zn+2(aq) + 2OH-(aq) --> Zn(OH)2(s)

6C)

MgSO4 + Pb(NO3)2

You should know by bnow that PbSO4 will precipitate

MgSO4(aq) + Pb(NO3)2(aq) --> MgSO4(aq) + Pb(NO3)2(s)

Split into atoms

Mg+2(aq) +SO4-2(aq) + Pb+2(aq) + 2NO3-(aq) --> Mg+2(aq) + 2NO3-(aq) Pb(NO3)2(s)

take out spectator ions

Mg+2(aq) +SO4-2(aq) + Pb+2(aq) + 2NO3-(aq) --> Mg+2(aq) + 2NO3-(aq) +Pb(NO3)2(s)

SO4-2(aq) + Pb+2(aq) -->  +Pb(NO3)2(s)

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